y(x^4-y^2)dx+x(x^4+y^2)dy=0

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Solution for y(x^4-y^2)dx+x(x^4+y^2)dy=0 equation:


Simplifying
y(x4 + -1y2) * dx + x(x4 + y2) * dy = 0

Reorder the terms for easier multiplication:
y * dx(x4 + -1y2) + x(x4 + y2) * dy = 0

Multiply y * dx
dxy(x4 + -1y2) + x(x4 + y2) * dy = 0
(x4 * dxy + -1y2 * dxy) + x(x4 + y2) * dy = 0

Reorder the terms:
(-1dxy3 + dx5y) + x(x4 + y2) * dy = 0
(-1dxy3 + dx5y) + x(x4 + y2) * dy = 0

Reorder the terms for easier multiplication:
-1dxy3 + dx5y + x * dy(x4 + y2) = 0

Multiply x * dy
-1dxy3 + dx5y + dxy(x4 + y2) = 0
-1dxy3 + dx5y + (x4 * dxy + y2 * dxy) = 0

Reorder the terms:
-1dxy3 + dx5y + (dxy3 + dx5y) = 0
-1dxy3 + dx5y + (dxy3 + dx5y) = 0

Reorder the terms:
-1dxy3 + dxy3 + dx5y + dx5y = 0

Combine like terms: -1dxy3 + dxy3 = 0
0 + dx5y + dx5y = 0
dx5y + dx5y = 0

Combine like terms: dx5y + dx5y = 2dx5y
2dx5y = 0

Solving
2dx5y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '2'.
dx5y = 0

Simplifying
dx5y = 0

The solution to this equation could not be determined.

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